A man invest "p" rs in one scheme. And "p+600" rs in another scheme. If both scheme offer him 8% simple interest. And after 2 year from both scheme he got 736 as interest.. them how much money he kept in 2nd scheme???

• answer will be 2600
  
• 9 years agoHelpfull: Yes(2) No(0)
• Ans:Rs.4600/-
  for 1 year interest is==>(0.08*(2*p+600))
  for 2 year interest is==>2*(0.08(2*p+600))
  Given 2*(0.08(2*p+600))=736
  p=4000
  Many spent in 2nd scheme is..(p+600)
  i,e(4000+600)
  =4600/-
  
• 9 years agoHelpfull: Yes(0) No(3)
• 1st scheme S.I=P*8*2/100=16P100
  2nd schema S.I=(p+600)*8*2/100=16P+9600100
  (16P/100)+((16P+9600)/100)=736
  P=2000
  Thus 2nd scheme P=2600
• 9 years agoHelpfull: Yes(0) No(0)