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A can do a piece of work in 12 days, B can do the same work in 8 days, and C can do the same job in 4/5th time required by both A and B. A and B work together for 3 days, then C complete the job. how many complete days did C work?
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- 2 1/4 days
A & B's 1 day work=(1/12)+(1/8)=5/24
So C's 1 day work= (4/5)*(5/24)=1/6
3 days work of A & B=3*5/24=5/8 & remaining work=3/8
So days required for C to complete the work=(3/8)/(1/6)=9/4 or 2 & 1/4 - 8 years agoHelpfull: Yes(5) No(1)
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