The average marks of a student in 8 subjects is 87. Of these, the highest marks are 2 more than the one next in value. If these two subjects are eliminated, the average marks of the remaining subjects are 85. What are the highest marks obtained by him?

• Ans:94
  total marks in 8 subject=87*8=696
  total marks of 6 subject=85*6=510
  marks in remaining 2 sub=696-510=186
  now ,
  let 2nd highest marks be :x
  so highest marks is:x+2
  x+x+2=186
  so x=92
  so highest marks= 92+2=94 Ans.
• 8 years agoHelpfull: Yes(36) No(0)
• It can be solved in simple way (without envolving complicated multiplications)
  
  avg marks of 8 sbjcts =87
  
  after removing marks of 2 consecutive highest marks subjects
  avg of 6 sbjcts = 85
  total score removed in removing 2 subjects = 2*6(2 marks from each of 6 subjects's score) + 87 +87 = 186
  
  difference between highest and 2nd highest score is 2
  so, x + x + 2 =186
  x = 92
  highest score = 92+ 2 =94
• 8 years agoHelpfull: Yes(4) No(0)
• ans :94
  let sum of all is x
  so x=87*8=696
  now let sum of 6 is y and y=85*6=510
  let next value is n
  so y+n+(n+2)=696
  510+n+n+2=696
  2n=696-512=184
  so n=92
  higest is 92+2=94 ans
• 8 years agoHelpfull: Yes(0) No(0)
• 94 is highest
  
• 8 years agoHelpfull: Yes(0) No(0)
• Total marks of 8 students=87*8=696
  similarly when we eliminate two subject then the remaining marks of 6 students is=85*6=510
  then difference=696-510=>186
  i'e lowest marks is x then highest marks will be x+2.
  so,x+x+2=186
  2x=186-2
  2x=184
  x=92.
  so,highest marks will be 92+2=>94
• 8 years agoHelpfull: Yes(0) No(0)