IBM
Company
Numerical Ability
Sequence and Series
96 64 128 192 128 256 288 192
Read Solution (Total 26)
-
- After 3 terms the series repears. So 4th 5th 6th term are 2* 1st 2nd and 3rd term repectively. While the 7th 8th 9th are 3* 1st 2nd 3rd terms. So ans=128*3=384
- 8 years agoHelpfull: Yes(53) No(2)
- 96 64 128
96*2 64*2 128*2=192 128 256
96*3 64*3 128*3=288 192 384
- 8 years agoHelpfull: Yes(50) No(1)
- the pattern
1st 2nd 3rd
96, 64, 128
4th number 192/2=96
5th number 128/2=64
6th number 256/2=128
7th number 288/3=96
8th number 192/3=64
9th number will be 128*3=484
ANS:- 484 - 8 years agoHelpfull: Yes(8) No(24)
- 384
96-64 = 32
then add the value to first number i,e 96+32 = 128
then 192-128 = 64
192+64=256
then
288 - 192 = 96
288 + 96 = 384
- 8 years agoHelpfull: Yes(6) No(0)
- yeah.. it is 384..
- 8 years agoHelpfull: Yes(4) No(1)
- Take first 3 numbers (96 64 128) multiply by 2 , you well get next three numbers (192 128 256)
Take first set (96 64 128) multiply by 3 , you well get 3rd set (288 192) - 8 years agoHelpfull: Yes(4) No(0)
- 2nd term x2 for every 3 numbers... so 192x2=384
- 8 years agoHelpfull: Yes(3) No(1)
- 96*2,64*2,128*2,96*3,64*3,128*3=384
- 8 years agoHelpfull: Yes(2) No(0)
- 96:64:128 = 3:2:4
192:128:256 = 3:2:4
288:192:x = 3:2:4
x = 384 - 8 years agoHelpfull: Yes(2) No(0)
- Ans is 384
96 192 288 96*2=192, 96*3=288
64 128 192 64*2=128, 64*3=192
128 256 384 128*2=256, 128*3=384
- 8 years agoHelpfull: Yes(2) No(0)
- 32*3 , 32*2 ,32*4 ,32*6 ,32*4 ,32*8 ,32*9 ,32*6
3 ,2 ,4 ,6 ,4 , 8 , 9 , 6 ( every number is related to third )
3 ->6 ->9
2 ->4->6
4->8->12
32*12=384 - 8 years agoHelpfull: Yes(2) No(0)
- [96,64,128] 96-64= 32+96=128
[192,128,256] 192-128=64+192=256
[288,192,?] 288-192=96+288=384 - 8 years agoHelpfull: Yes(2) No(0)
- All are multilpes of 32.
Taking 32 as Common we get-
3 2 4 6 4 8 9 6
After that consider above nmbers as a group of three like 3,2,4 6,4,8(2 times of 3,2,4) 9,6,_(3 times of 3,2,4) so, next third term is 12.
Hence, final answer is--- 12*32=384 - 8 years agoHelpfull: Yes(2) No(0)
- 384
64*2=128
128*2=256
192*2=384 - 8 years agoHelpfull: Yes(2) No(0)
- After 3 terms the series repears. So 4th 5th 6th term are 2* 1st 2nd and 3rd term repectively. While the 7th 8th 9th are 3* 1st 2nd 3rd terms. So ans=128*3=384
- 8 years agoHelpfull: Yes(2) No(0)
- 384= 24*16
all the sequence is:
8*12, 8*8, 8*16, 16*12, 16*8, 16*16, 24*12, 24*8, 24*16 - 8 years agoHelpfull: Yes(1) No(1)
- 24
quotients after devide by 16 are 6 4 8 12 8 16 18 12
take set of three result.
1st set: 6 4(6-2) 8(6+2)
2nd set: 12 8(12-4) 16(12+4)
3rd set will be: 18 12(18-6) 24(18+6)
In every set the no to be subtract should be 2 more such as 2, 4, 6,... - 8 years agoHelpfull: Yes(1) No(1)
- (96 , 64 , 128),(192 , 128 , 256),(288 , 192 , ?)
-32 +64 -64 +128 -96 +192
inside 1st parenthesis,1st term-32 gives 64 i.e. 96-32->64, which is the 2nd term and then 2nd term +second term gives the 3rd term i.e. 64+64->128.
Similarly, solve for all parenthesis and we will get 192+192 -> 384 as Ans. - 8 years agoHelpfull: Yes(1) No(0)
- ans:96*2=192
64*2=128
128*2=256 then
96*3=288
64*3=192
128*3=384
- 8 years agoHelpfull: Yes(1) No(0)
- 96 64 128
96*2=192
64*2=128
128*2=256
96*3=288
62*3=192
128*3=384
384 ans - 8 years agoHelpfull: Yes(1) No(0)
- 96,64,128,96*2,64*2,128*2,96*3,64*3,128*3=384
- 8 years agoHelpfull: Yes(1) No(0)
- (1st,2nd,3rd)*2=4th,5th,6th
(4th,5th,6th)*1.5=7th,8th,9th
hence 9th=384 - 8 years agoHelpfull: Yes(1) No(0)
- 31,14,18,30,15,19,29,20,16.......
after 31 3rd value is 30 then after 30 3rd value will 29....
same we can see after 14, 3rd value is 15 and after 18, 3rd value is 19...
means pair of three.
- 8 years agoHelpfull: Yes(0) No(0)
- fist series: 96 192 288
( 64 128) (128 256) (192 192*2)
so its 364 - 8 years agoHelpfull: Yes(0) No(1)
- 128*3=384 becoz of terms
- 8 years agoHelpfull: Yes(0) No(0)
- 96-64=32
128-64=64(32*2)
192-128=64
256-128=128(64*2)
288-192=96
so ...x-192=192(96*2)
x=384 - 8 years agoHelpfull: Yes(0) No(0)
IBM Other Question
31,14,18,30,15,19
In the following questions select the number(s) from the given options for completing the given series.
Q.2 36,24,15,9,6? a) 3 b) 6 c) 0 d) 2
Q.3 98,72,14,? a) 8 b) 6 c) 4 d) 2
Q.4 69,55,26,13,? a) 3 b) 6.5 c)13 d) 4