IBM
Company
Logical Reasoning
Number Series
In the following questions select the number(s) from the given options for completing the given series.
Q.2 36,24,15,9,6? a) 3 b) 6 c) 0 d) 2
Q.3 98,72,14,? a) 8 b) 6 c) 4 d) 2
Q.4 69,55,26,13,? a) 3 b) 6.5 c)13 d) 4
Read Solution (Total 16)
-
- Q3.
9 x 8 = 72
7 x 2 = 14
1 x 4 = 4
Ans: c
- 8 years agoHelpfull: Yes(27) No(4)
- Q.2
36-24=12
24-15=9
15-9=6
9-6=3
6-6=0
Therefore, answer is b) 6. - 8 years agoHelpfull: Yes(15) No(4)
- q4. 6*9+1=55
5*5+1=26
2*6+1=13
so
1*3+1=4 ans - 8 years agoHelpfull: Yes(9) No(0)
- 6 x 9 + 1 = 55
5 x 5 + 1 = 26
2 x 6 +1 = 13
1 x 3 + 1 = 4
Ans: d - 8 years agoHelpfull: Yes(7) No(1)
- Q.2 answer = 0
36 24 15 9 6
is 36-24=12
24-15=9
15-9=6
9-6=3
6-0=6
- 8 years agoHelpfull: Yes(6) No(11)
- 36-12=24
24-9=15
15-6=9
9-3=6
6-0=6
- 8 years agoHelpfull: Yes(4) No(0)
- 36,24,15,9,6?
12*3,8*3,5*3,3*3,2*3,1*3
hence 3 - 8 years agoHelpfull: Yes(4) No(1)
- Q.2
36-24=12
24-15=9
15-9=6
9-6=3
6-6=0
Therefore, answer is b) 6.
Q3.
9 x 8 = 72
7 x 2 = 14
1 x 4 = 4
Ans: c
6 x 9 + 1 = 55
5 x 5 + 1 = 26
2 x 6 +1 = 13
1 x 3 + 1 = 4
Ans: d - 8 years agoHelpfull: Yes(3) No(0)
- q.2=>d
q.3==>d(all numbers are divisible by 2)
- 8 years agoHelpfull: Yes(1) No(4)
- q.2==> c
q.3==> d
- 8 years agoHelpfull: Yes(1) No(3)
- Answer (b) 6.
Divide the series by 3 , we get 12,8,5,3,2,x
calculate the difference between two consecutive numbers, we get 4,3,2,1,y
Hence y = 0,
therefore x = 2,
and ? = 2*3 = 6.
- 8 years agoHelpfull: Yes(1) No(1)
- Q2.)36-12=24
24-9=15
15-6=9
9-3=6
so 3-3=0ANS.
Ans is 0.
Q 3)9*8=72
7 *2=14
4*1=4 ANS.4
Q4.)6*9=54+1=55
5*5=25+1=26
2*6=12+1=13
1*3=3+1=4ANS=4
- 8 years agoHelpfull: Yes(1) No(0)
- 2q :b)6
3*12,3*8,3*5,3*3,3*2
after that cal diff b/w 12,8,5,3,2
then next will be 2 so 3*2=6 - 8 years agoHelpfull: Yes(0) No(1)
- hkhkhjhjhlj;j;
- 8 years agoHelpfull: Yes(0) No(4)
- 36-24=12,24-15=9,15-9=6,9-6=3,6-0=6
so answer will be 6
9*8=72,7*2=14,1*4=4
9*6+1=55,5*5+1=26,2*6+1=13,1*3+1=4 - 8 years agoHelpfull: Yes(0) No(0)
- Q2 answer 6
- 8 years agoHelpfull: Yes(0) No(0)
IBM Other Question