4 men can check exam papers in 8 days working 5 hours regularly. What is the total hours when 2 men will check the double of the papers in 20 days?

• total work done=4*8*5=160units
  now work=2*160=320units
  now,2 men work for 20days,let x be the hours.
  therefore, 2*20*x=320
  x=8 hours
  
• 9 years agoHelpfull: Yes(22) No(0)
• m1*d1*h1=m2*d2*h2
  4*8*5=2*20*h2
  160=40h2
  h2=4
  but bcs of double papers it becomes 4*2= 8 hours
• 8 years agoHelpfull: Yes(19) No(0)
• 8 hrs
  4*8*5 =w
  2*20*h=2w
  
• 9 years agoHelpfull: Yes(12) No(7)
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• 9 years agoHelpfull: Yes(6) No(2)
• 4*8*5/1=2*20*h/2
  h=8hours
• 9 years agoHelpfull: Yes(6) No(1)
• 4*8*5/1=2*20*h/2
  => h=8
• 9 years agoHelpfull: Yes(4) No(1)
• 8*5=40 hrs per men overall 4 men 4*40=160 hrs of work so 40hrs work is 25percentage
  for 160hrs of work 2 men will make the work as 80hrs per person for 20 days i.e., 80/20=4hrs per day.
• 9 years agoHelpfull: Yes(3) No(3)
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• Yes Sundar :) Please mail me dude...
• 9 years agoHelpfull: Yes(1) No(1)
• Let a man can do 1 unit of work in 1 hour.
  Total units of work = 4 x 8 x 5 = 160 units.
  Now work = 2 x 160 = 320 units.
  Now 2 men work for 20 days. Let in x hours they have to work per day.
  Now total work = 2*x*20 = 40 x
  40x = 320 => x = 320/40 = 8 hours.
• 9 years agoHelpfull: Yes(1) No(0)
• yes.....i can
  
• 9 years agoHelpfull: Yes(1) No(1)
• (m*d*h)/w=(m2*d2*h2)/w2;
  w1=w, w2=2w;
  so ans is 8hrs
• 8 years agoHelpfull: Yes(1) No(0)
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• 9 years agoHelpfull: Yes(0) No(1)
• 1 men 1 days work=1/4*8*5
  =1/160
  
• 9 years agoHelpfull: Yes(0) No(0)
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• Am having my TCS exam tomorrow(23-1-16) Guys if you know any imp que ping me @amarvcet@gmail.com..thanks in adv...
• 9 years agoHelpfull: Yes(0) No(1)
• 160 hours ....as man *days / work we have 160
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• 9 years agoHelpfull: Yes(0) No(1)
• LET CHECKING EXAM PAPER =W
  NOW , MAN ~ W
  MAN~ (1/T) , T STANDS FOR TIME
  SO, MAN ~(W/T)
  SO , (MT/W)= CONSTANT
  >(M1T1/W1)=(M2T2/W2)
  HERE M1=4, T1= 8*5=40, W1=W, M2=2, T2= 20*X, W2=2W ANS- X=8HOURS PER DAY
• 8 years agoHelpfull: Yes(0) No(0)
• 4 men work for 8*5=40 hrs,so total work done=40*4=160
  2 men will work for 20 days & check double the papers,so
  total work for them will be 2*160=320
  2 men work for 20 days & x hrs daily(say)
  so,2*20*x=320
  or x=8
• 8 years agoHelpfull: Yes(0) No(0)
• first 4:8:5=2:x:20
  x=8 hours
• 8 years agoHelpfull: Yes(0) No(0)
• (4*8*5)/1=(2*20*x)/2
  160*2=40*x
  x=320/40
  x=8 hours
• 7 years agoHelpfull: Yes(0) No(0)
• W=checking the papers
  W2=2*W1
  w1=M1*D1*H1
  w2=M2*D2*H2
  the hours required to complete the double no. of papers : H2=(W2*M1*D1*H1)/(W1*M2*D2)
  H2=(2W1*4*8*5)/(W1*2*20)
  H2=8hours
• 6 years agoHelpfull: Yes(0) No(0)
• ans is 8 hrs
  p*h*d=w
  4*5*8*2x=2*20*y*x
  y=8h
• 5 years agoHelpfull: Yes(0) No(0)
• total work done=4*8*5=160units
  now work=2*160=320units
  now,2 men work for 20days,let x be the hours.
  therefore, 2*20*x=320
  x=8 hours
• 1 year agoHelpfull: Yes(0) No(0)