Elitmus
Exam
Numerical Ability
Averages
batting avg of 40 innings of a player is 52.his highest score exceeds lowest score by 172 runs.two innings excluded,avg of remaining 38 innings is 40,his highest score?
Read Solution (Total 9)
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- consider highest and lowest score be H and L
total score in 4o innings =40*52
total score in 38 innings =38*40
remaning are lowest and highest scores that is 40*52-38*40=H+L=560---->1
given that H-L=172 -------->2
by sloving 1 and 2 we get
H=366 - 9 years agoHelpfull: Yes(21) No(0)
- Theoretically RAVI is correct.But As per data provided in this question is wrong logically.Becoz if Highest is 366 and lowest is 194 then average should flip in 194 to 366.
- 9 years agoHelpfull: Yes(9) No(1)
- Highest score be x
Lowest score= x-172
52*40-(x+(x-172))=38*40
X=366
- 9 years agoHelpfull: Yes(5) No(0)
- Two innings run is 40*52-38*40 =560.
Now average of remaining inning is 40.
Now ,If you divide 560 in two equal part is 280.And then the lowest score is 108.
So,question is wrong. - 9 years agoHelpfull: Yes(2) No(1)
- his total run in 40 innings = 40*52=2080
and if we exclude 2 inninds his total runs become=38*40=1520
if we suntract these two we will get the runs of the two excluded innings=2080-1520=560
which is the sum of the lowest and highest innings H+L=560and it is given H-L=172
by solving these two eq. we have highest score is 366 - 9 years agoHelpfull: Yes(1) No(0)
- data is wrong i think he typed 40 instead of 50
- 9 years agoHelpfull: Yes(1) No(0)
- 40*52=2080
38*40=1520
let be the lowest score- 'x'
and highest score is- 'x+1'
and 2080-1520=560
two innnings
x+x+172=560
2x=488
x=244
finally highest score is 244+172=416 - 9 years agoHelpfull: Yes(1) No(4)
- Total runs 40 innings is 40*52=2080
Total runs in 38 innings is 38*40=1520
Differences between highest and lowest score is H-L=172
Therefore H+L=560
Solving above equation we get L=194 and H=366 - 9 years agoHelpfull: Yes(0) No(0)
- ans is 366
let highest score=x
lowest score=x-172
then (40*52)-(x+x-172)=38*40
solve this - 7 years agoHelpfull: Yes(0) No(0)
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