area of the rectangle field is 144m2.if length is increased by 5 metres.its area increases by 40 m2.what is the length of the field?

• 18 m.
  
  If length=x, breadth=y, then xy=144 and
  (x+5)y=144+40 or xy+5y=184
  substituting xy=144, y=8, so x=144/8=18
  
  *Pl. ignore my earlier solution due to mistake.
• 8 years agoHelpfull: Yes(22) No(0)
• Let the lenght be l and bredth be b.
  L*b=144
  When length increased by 5 metres.Area,increased by 40sqm
  New area (l+5)b=184
  
  Solving above equation we get
  B=8
  L=18
• 8 years agoHelpfull: Yes(5) No(0)
• Let Length= L , and Breadth= B
  then L*B=144
  or (L+5)B=144+40, LB+5B=184
  144+5B=184, 5B=40
  B=8 AND THEN PUT B VALUE IN L*B=144,
  8L=144 THEN L=18
  L=18 AND B=8
  
• 8 years agoHelpfull: Yes(3) No(0)
• i cant believe such question could be asked in elitmus
• 8 years agoHelpfull: Yes(1) No(0)
• 7.2 m.
  
  If length=x, breadth=y, then x*y=144 ---(i) &
  (x+2)*y=144+40, xy+2y=184 or 2y=40, y=20,
  Substituting 'y' in (i), x=144/20=36/5=7.2
• 8 years agoHelpfull: Yes(0) No(5)
• l*b=144
  (l+5)*b=184
  {(l+5)*b}/(l*b)=184/144
  144*l+5*144=184*l
  5*144=40*l
  l=18
• 8 years agoHelpfull: Yes(0) No(0)
• Answr .... 8 and 18
• 8 years agoHelpfull: Yes(0) No(0)
• l*b=144
  (l+5)*b=184
  
  l=18m
• 8 years agoHelpfull: Yes(0) No(0)
• let length =a
  breadth=b
  then ab=144
  if length is increased by 5 and area by 40 then
  length=a+5
  so (a+5)b=184 for further solving the 2 eq. we have
  a=8 ,b=18
• 8 years agoHelpfull: Yes(0) No(0)
• xy=144
  (x+5)y=144+40
  xy+5y=184
  (144/y)y+5y=184
  144+5y=184
  5y=40
  y=8
  
• 8 years agoHelpfull: Yes(0) No(1)