The time required for completing 3 tasks:type-1,type-2,type-3,by three carpenters is given in the table below.time specified in the table is for manufacturing single unit.

c1 c2 c3(c=carpenter)

type1 3 2 5

type2 6 5 4

type3 5 5 6


All the three carpenters start working simultaneously on one task each,with an objective to finish all the tasks as early as they can


1.C1 should work on:
A.Type1 B.Type2 c.Type3 D.none of the above


2.C3 should work on:
A.Type1 B.Type2 c.Type3 D.can't say


3.In how many hours can the entire work be finished?
A.4hr B.5Hr C.6hr D.7hr


4.In how many hours can 5 units of each type be prepared?
A.55hr B.25hr C.35hr D.10hr

5.If c2 is ristricted to prepare only Type-3 ,then c1 should work on:

A.Type1 B.Type2 c.Type3 D.can't say

• 1-c (As c2 takes less time in type 1 among all 3 so c2 work on type 1...Similarly,c3 on type 2 and c1 on type 3)
  2-b
  3-b (longest time taken by a carpenter is 5 that is by c1)
  4-a (type1-2x5=10,type2-4x5=20,type3-5x5=25...so total time =10+20+25=55hr)
  5-a (because c1 got less time in type 1 as compared to c3)
• 8 years agoHelpfull: Yes(19) No(5)
• 4. As longest time for preparing single unit is 5hrs. so for 5units .. 5*5=25hrs.
  answer is B.
• 7 years agoHelpfull: Yes(2) No(0)
• i need answer for this
• 9 years agoHelpfull: Yes(0) No(1)
• please give the answers for this question
• 9 years agoHelpfull: Yes(0) No(0)
• 1-c
  2-b
  3-b
  
  5-a
• 9 years agoHelpfull: Yes(0) No(1)