A hexagon of side a cm is folded along its edges to obtain another hexagon
What is the % decrease in the area aof orignal hexagon

• when its folded along its edges.. how it forms another hexagon.? please explain
• 8 years agoHelpfull: Yes(10) No(2)
• 75% is answer
  As we know, area of hexagon is = (3√3)(a^2)/2
  now lets take a=2
  then area = 6√3
  after fold it will side become half ; a=1
  new area = 1.5√3
  percentage= 6√3/ 1.5√3* 100=25 %
  so decrease in area =100 - 25=75%
  
• 8 years agoHelpfull: Yes(6) No(9)
• area of hexagon=3√3 /2 * a^2
  
  that means area is proportional to square of side a. If we decrease the size by x , then area will be
  = 3√3 /2 * (a-x)^2
  
  that means decrease will be =( 3√3 /2 * a^2) -(3√3 /2 * (a-x)^2)
  % decrease= ((a^2)-(a-x)^2) / a^2
  
  
  
  
• 8 years agoHelpfull: Yes(0) No(5)
• assume side= 4
  initial area=(3*sqrt(3)*a^2)/2 =41.3923
  after fold side=2
  The area folded = 6* area of each triangle
  =6((2*2*sin(120))/2)
  =10.3923
  decrease in area= (10.3923/41.5692)*100
  =25%
• 5 years agoHelpfull: Yes(0) No(0)