Capgemini
Company
Numerical Ability
Arithmetic
A girl wants to buy a bag. she decides to save her pocket money to buy it. on the first day, she saves Rs.10, and on every subsequent day, she saves Rs.10 more than the money she has saved on the previous day would the girl be able to save Rs.1200 for her bag?
a.12th day
b.13th day
c.13th day
d.15th day
Read Solution (Total 6)
-
- a=10, d=10, n=? sum=1200
sum= n/2[2a+(n-1)d]
1200=n/2[20+(n-1)10]
2400=n[20+10n-10]
2400=n[10n-10]
2400=10 n^2+10n
10^2+10n-2400=0
n=15 or n=-16
so n=15
hence 15th day - 8 years agoHelpfull: Yes(21) No(0)
- Answer is D on 15th day
- 8 years agoHelpfull: Yes(4) No(0)
- 10+20+30+.................................150=1220
- 8 years agoHelpfull: Yes(1) No(1)
- 10+20+30+40......n th term
10(1+2+3+4+......n th number ) =10*n(n+1)/2
Sum of all numbers=1200
10*n(n+1)/2=1200
n^2+n-240=0
n=15 - 6 years agoHelpfull: Yes(1) No(0)
- 13th day formulae tn=a(n-1)d
- 8 years agoHelpfull: Yes(0) No(12)
- on 15th day
- 7 years agoHelpfull: Yes(0) No(0)
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