if we roll 2 dice at a time then what is the probability that the no. obtained frm both of them makes a sum of either 3 or 4

• total sample space=36 and total chances of occurence is 5 those are (1,2) (2,1) (2,2) (1,3) (3,1) . hance probability=5/36
• 8 years agoHelpfull: Yes(10) No(6)
• It will be 5/9
• 8 years agoHelpfull: Yes(7) No(1)
• Ans will be 5/36........ i can bet
• 8 years agoHelpfull: Yes(6) No(0)
• the question had multiple of 3 or 4.
  may be i'm wrong but that's what i remember.
• 8 years agoHelpfull: Yes(4) No(0)
• no of sample space = (1,1) to (6,6)=36 and no of events=(1,2) (1,3) (1,5),(2,1),(2,2) (2,4) (2,8) and so on =20 so ans is 20/36=5/9
• 8 years agoHelpfull: Yes(3) No(5)
• but they askd only for sum which is either 3 or 4 then how 92,8) , (1,5) (4,2) are considered?
• 8 years agoHelpfull: Yes(2) No(0)
• total sample space=36
  total chances of occurence is 5 ----(1,2) (2,1) (2,2) (1,3) (3,1) .
  hence probability=5/36
• 5 years agoHelpfull: Yes(2) No(0)
• The question was probability of number such that sum is a multiple of 3 or 4.
• 8 years agoHelpfull: Yes(1) No(0)
• i too got the same 5/36 bt thats nt in the optns.. i thinks its a dummy bit then
• 8 years agoHelpfull: Yes(0) No(1)
• ans is 20÷36 so 5/9
• 8 years agoHelpfull: Yes(0) No(0)
• Ans will be
  5/9
• 8 years agoHelpfull: Yes(0) No(0)
• Answer is 5/9
• 8 years agoHelpfull: Yes(0) No(0)
• 12/36+9/36=7/12 but this ans not in option.... ?
• 8 years agoHelpfull: Yes(0) No(0)
• Its answer is 1/3
  Total 36 events out of those
  No.3,4,6,8,9,12 for one condition+same second condition(exchange dice values 1&2)=12
  
  So 12/36=1/3
• 8 years agoHelpfull: Yes(0) No(0)
• 5/9
  because we have 20 posibilities out of 36 so we have to write it 20/36=5/9
  
• 8 years agoHelpfull: Yes(0) No(0)
• Ans.5/9
• 8 years agoHelpfull: Yes(0) No(0)
• Answer is 5/36 it is correct
• 7 years agoHelpfull: Yes(0) No(0)
• answer is 5/36
• 7 years agoHelpfull: Yes(0) No(0)
• 5/36--as there is 5 possiblities that is (1,2),(1,3)(2,1)(3,1)(2,2)out of 36
• 6 years agoHelpfull: Yes(0) No(0)