if there are 11 no.s such that the average of first six no.s is 42 and the average of last 6 no.s is 54
then find the 6th no.

• sum of first 6 no.s = 42*6 =252
  sum of lst 6 no.s = 54*6 = 324
  as there are 11 no.s let they be a b c d e f g h i j k
  here 6th no. is considered both in 1st 6 no.s and last 6 no.s
  soo substractng both of them gives 324-252 =72
  
  i dnt knw how to find after this
• 8 years agoHelpfull: Yes(3) No(2)
• I got answer 56.
  Anyone got?
  please reply
• 8 years agoHelpfull: Yes(3) No(1)
• yes ans is 56
• 8 years agoHelpfull: Yes(3) No(1)
• answer will be 26(if the data provided here and in the comments are correct)
  hint : sum of 11 nos. = 11 x 50
  sum of first 6 = 6 x 42
  sum of last 6 = 6 x 54
  
  so now, sum of 11 = sum of first 6 + sum of last 6 - 6th term
  
  
• 8 years agoHelpfull: Yes(2) No(0)
• average of 11 number is 50
• 8 years agoHelpfull: Yes(1) No(0)
• I got 26 as answer.
• 8 years agoHelpfull: Yes(1) No(0)
• where is avg of 11 people that is given in paper
  
• 8 years agoHelpfull: Yes(0) No(0)
• im the one posting the above qstn and im pretty sure that total average of 11 no.s is nt given in the problem.
• 8 years agoHelpfull: Yes(0) No(0)
• guys anyone remember that" freelancer" question??
• 8 years agoHelpfull: Yes(0) No(0)
• HOW U GET THE AVG OF 11 NOS IS 50?????????????
  
• 8 years agoHelpfull: Yes(0) No(1)
• first 6->42*6=252
  last 6->54*6=324
  (324-252)=72 answer
  
• 8 years agoHelpfull: Yes(0) No(0)
• 54-42=12
  12*6=72
• 8 years agoHelpfull: Yes(0) No(0)
• avg =50 so total sum of 11 numbers=550
  let 6th no is x,so acc to the given condition
  sum of first 5 nos=6*42-x=252-x
  sum of last 5 nos=54*6-x=324-x
  so 6th term x=550-(252-x)-(324-x)
  550-252+x-324+x
  2x+550-576
  2x-26
  x=13
• 7 years agoHelpfull: Yes(0) No(1)
• Average of 11 numbers is 50 which is not given in the question.So the final answer will come as (6×42+6×54)-(11×50)=26
• 6 years agoHelpfull: Yes(0) No(0)