f(x) = logax + logbx + logcx if logax>=1

and logax>logbx>logcx

whats the minimum value of f(x) ?

a. 1
b. 2
c. 3
d.none of above

• minimum value of logcx may be -infinite . so d option is currect
• 8 years agoHelpfull: Yes(5) No(0)
• can u explain rajesh verma please
• 8 years agoHelpfull: Yes(1) No(0)
• Ans-(d) Since double derivative of f(x) is negative minimum value can't be calculated
  
• 8 years agoHelpfull: Yes(1) No(1)
• d.none of above
  
  minimum value of logax=1
  and logax>logbx>logcx
  so logbx and logcx must be greater than 1
  thus logax + logbx + logcx>3
• 8 years agoHelpfull: Yes(0) No(13)
• sorry solution is incorrect took logcx>logbx>logax instead of logax>logbx>logcx
• 8 years agoHelpfull: Yes(0) No(1)
• @himaan see the valu of log totally depend upon base . and there is no relation between base in this question given ( base means a b c) so c may be 0
• 8 years agoHelpfull: Yes(0) No(1)
• abc are not base the base was not given to us
• 8 years agoHelpfull: Yes(0) No(1)
• given logax>=1 and also given logax>logbx>logcx,
  suppose if we take logax=1 so logbx
• 8 years agoHelpfull: Yes(0) No(1)
• log value can be at minimum 0
  but logax>=1 is given so min log value can be 1 since lobx,logcx less than logax
• 7 years agoHelpfull: Yes(0) No(2)