In a party men drink only beer, women drink only wine , sons drink only orange juice and daughters drink only apple juice. There are 1.05L of beers, 1.05L of wine 3.5L of orange juice and 4.9L of apple juice. If every one has the same drinking capacity then what can be the minimum number of people present at the party?

• Take HCF of 1.05,1.05,3.5,4.9.
  which is 0.35.
  Then divide each quantity by HCF to get the number people drinking that particular beverage.
  i.e 3+3+10+14=30.
  
• 8 years agoHelpfull: Yes(43) No(11)
• HCF of two or more fraction is -------->HCF of Numerator/LCM of Denominator
  so, 105/100, 105/100, 35/10, 49/10
  Take the HCF of 105, 105, 35, 49 = 7 & LCM of 100, 100, 10, 10 = 100
  so, the HCF is 0.07
  and the no of people present in the party is 15+15+50+70 = 150.
• 8 years agoHelpfull: Yes(13) No(1)
• 150 is correct answer...
  by taking LCM SAME CAPACITY WILL come .07L
  
• 8 years agoHelpfull: Yes(6) No(3)
• Take HCF of 1.05,1.05,3.5,4.9.
  which is 0.07.
  Then divide each quantity by HCF to get the number people drinking that particular beverage.
  i.e 30+30+50+70=150.
  but in last line of question it mention that minimum number of people CAN BE present so it CAN BE beer drinkers or wine drinkers .
  i.e 30 is the answer
• 8 years agoHelpfull: Yes(5) No(5)
• why we take hcm here why not lcm jst b'coz here asked min not max
• 8 years agoHelpfull: Yes(3) No(0)
• Shubham is right. I also marked 30. And the options were 14,21,27 and 30. So 150 is definitely incorrect.
• 8 years agoHelpfull: Yes(2) No(1)
• It should be 150.
• 8 years agoHelpfull: Yes(1) No(2)
• hcf of given quantity that is 0.07
  divide each quantity by hcf sum their results
  1.05/0.07+1.05/0.07+3.5/0.07+4.9/0.07=150
• 6 years agoHelpfull: Yes(0) No(0)