Capgemini Company Numerical Ability Age Problem

the sum of the ages of a,b and c was 52 three years ago.Four years ago B,who is a year younger than C,was 1 1/2 times as old as A.The sum of the ages of B and C two years hence,will be

Read Solution (Total 3)

49 years

Present sum of ages of a,b & c= a+b+c =52+9=61 ---(i)
Given b is a year younger than c, so b+1=c ---(ii)
Also b-4=(a-4)*3/2 or 2b -8=3a-12 or 2b -3a= -4 ---(iii)
Substituting c=b+1 from (ii) in (i), a+2b=60 ---(iv)
On solving (iii) & (iv), a=16, b=22 so c=23
So sum of the ages of b & c two year hence= (b+2)+(c+2)=24+25=49
8 years agoHelpfull: Yes(14) No(5)

a+b+c =52 3 years ago
at present 52+9= 61 (every age vil b incresed by 3)
4 years ago 61-4=57
B= 3/2 of A ( B was 3/2 times old as A)
C = B is a year younger than C i.e., B+1

A+( 3/2 of A)+ (3/2 of A +1) = 57

On Solving We get A = 14
B = 21 , C= 22

After 2 years B+C = (21+2) + (22+2)
= 23+24
= 47
C=
8 years agoHelpfull: Yes(3) No(6)
Present sum of ages of a,b & c= a+b+c =52+9=61 ---(i)
Given b is a year younger than c, so b+1=c ---(ii)
Also b-4=(a-4)*3/2 or 2b -8=3a-12 or 2b -3a= -4 ---(iii)
Substituting c=b+1 from (ii) in (i), a+2b=60 ---(iv)
On solving (iii) & (iv), a=16, b=22 so c=23
So sum of the ages of b & c two year hence= (b+2)+(c+2)=24+25=49
7 years agoHelpfull: Yes(2) No(0)

Capgemini Other Question

the ratio of the ages of aunt agatha and uncle roger is 5:6,the same as the ratio of the ages of thier or their children,suzaman and beard.if the the sum of the ages of suzanne and aunt agatha,five years ago,was 60,what will be the sum of the ages of bernard and uncle roger five years hence? if A alone does the work in 15 days,how much time will A and B take working together to complete the job,given that A is 30% more efficient than B?