In a party , where there were 200 quests, 60% had veg food, 50% had non veg, 30% of guest had both veg and non veg, how many % did not dine at the party?
a-30
b-35
c-40
d-45

• Total guests =200
  Dine members=(veg+nonveg - both)%
  (60+50- 30)%
  =80%
  Not Dine members=100%- 80%
  =20% of 200
  =40 members
• 8 years agoHelpfull: Yes(37) No(1)
• Option: C
  using ven diagram i solved this
  Total 200 people of this 60% -Veg food = 120
  Total 200 people of this 50% - non- Veg food =100
  30% both veg and non veg=60
  veg only=60
  only non veg=40
  both=60
  therefore people didnt dine=> 60+60+40+x=200
  =>x=40
• 8 years agoHelpfull: Yes(15) No(2)
• Veg 60% = 120 , Non Veg 50% = 100, Common 30% = 60
  Total people who ate = 120 +100 -60=160
  Thus people who didn't eat = 200 -160 = 40
  
  Ans: C
• 8 years agoHelpfull: Yes(10) No(1)
• why not 20...It ask about %
• 8 years agoHelpfull: Yes(5) No(0)
• let people not took part=x;
  a U b= a+ b-a intersactin b;
  200-x=120+100- 60;
  x=40 ie 20%
• 8 years agoHelpfull: Yes(2) No(0)
• c 120+100+60-200=80 which is opt c
  
• 8 years agoHelpfull: Yes(1) No(6)
• from 200,60% veg means 120
  50% non veg means 100
  30% both means 60
  so % did not dine=200-120-100+60=40
• 8 years agoHelpfull: Yes(1) No(0)
• P(AUB) = P(A) + P(B) -P(A^B) = 60% + 50% - 30% = 80%
  So, 80% of 200 = 160
  therefore, 200 - 160 = 40.
  40 members.
• 7 years agoHelpfull: Yes(1) No(0)
• 60*200/100+50*200/100-30*200/100=160 and remaining 40 members
  
• 8 years agoHelpfull: Yes(0) No(0)
• Total guests =200
  Dine members=(veg+nonveg - both)%
  (60+50- 30)%
  =80%
  Not Dine members=100%- 80%
  =20% of 200
  =40 members
• 8 years agoHelpfull: Yes(0) No(0)
• C. 40
  as,
  Veg = 60% ie 120
  Non-Veg = 50% ie 100
  Both : Veg U nVeg = 30 % ie 60
  200 = dont't eat + veg + nVeg - Veg U nVeg
  200 = X + 120 + 100 -60
  X = 40
• 8 years agoHelpfull: Yes(0) No(0)
• n(Nveg) = 50%(200) = 100
  n(veg)=30%(200) = 120
  n(both)=60%(200)=60
  n(Nveg U veg) = n(Nveg)+n(veg)- n(Nveg - veg))
  =120+100-60= 160
  => 200 - 160 = 40
• 7 years agoHelpfull: Yes(0) No(0)
• answer is c-40
  solution is:-
  veg=60%, non-veg=50%, veg and non-veg=30%
  so, veg or non-veg=60%+50%-30%=80%
  so, who don't eat either veg or non-veg i.e. who didn't eat any food= 100%-80%=20%
  
  means, 20% of 200=40 quests didn't eat any food.
• 7 years agoHelpfull: Yes(0) No(0)
• P(A U B) =P(A) + P(B) - P(A n B)
  P(A)=60/100
  P(B)=50/100
  P(A n B)=30/100
  Therefore, P(A U B)=60/100 + 50/100 - 30/100
  P(A U B)=80/100
  Required is P (A' U B')=1- P(A U B )
  P(A' U B')=20/100
  Hence , no of people who didnot dine is 20/100*200=40
• 7 years agoHelpfull: Yes(0) No(0)
• answer is 20%
• 7 years agoHelpfull: Yes(0) No(0)
• 40 perfect.
• 7 years agoHelpfull: Yes(0) No(0)
• 200 quest= 40 100*200=80 quest veg food
  200 quest= 50100*200= 100 non veg food
  200 quest = 70100*200 = 140 both
  dine = (80+100-140) = 40 member not dine
• 5 years agoHelpfull: Yes(0) No(0)