How many odd numbers are possible between 1 to 10000? find out the number of odd number of digits?

• There are always one odd and one even no. And the question is odd no. Between 1 to 10000
  So we have to find no. Between 1 to 10000 so we should not includes 1
  10000/2 -1=4999 is the answer
• 8 years agoHelpfull: Yes(25) No(3)
• total odd no - 5000
  no of odd digits are
  1- 10 = 5
  11-20 - 14
  21-30 - 5
  31 - 40 = 14
  41-50 = 5
  51 - 60 = 14
  61 - 70 = 5
  71 - 80 = 14
  81 - 90 = 5
  91 - 99 = 14
  
  1digit - 5
  2digit - 45*2
  3 digit- 450*3
  4 digit - 4500*3
  total - 14945
• 8 years agoHelpfull: Yes(11) No(16)
• a=1,d=2,
  now, 1000=1+(n-1)2, 999=1+(n-1)2,n=998/2+1,n=1000/2
  n=500
• 8 years agoHelpfull: Yes(7) No(10)
• If you are considering 1 then Ans is 5000
  If not then it is 4999
• 8 years agoHelpfull: Yes(6) No(1)
• 1digit - 5
  2digit - 45*2
  3 digit- 450*3
  4 digit - 4500*3
  total - 14945
• 8 years agoHelpfull: Yes(5) No(15)
• last odd no will be 9999 so 9999=1+(n-1)2 (AP with d=2 and tn=9999)
  n==5000 odd no's
  second part :
  no of odd number of digits .
  1....9=9
  100......999=900
  10000
  so total no of odd no of digits =9+900+1=910
• 8 years agoHelpfull: Yes(2) No(3)
• nos of odd numbers bw 1-10=5
  nos of odd numbers bw 11-99 can be calculated as:
  11, 13 , 15,....99 so 99=11+(n-1)2 .... therefore n =45.
  similarly for 100-999 it will be 450
  and for 1000-10000 it will be 4500.
  So the total nos of odd numbers are 5+45+450+4500=5000
• 8 years agoHelpfull: Yes(2) No(2)
• number of terms n=(L-a)/d+1
  n=(9999-1)/2+1=5000
• 8 years agoHelpfull: Yes(2) No(2)
• l=a+(n-1)*d
  1+3+5+...........+9999
  9999=1+(n-1)2
  9998/2=(n-1)
  4999+1=n
  n=5000
• 8 years agoHelpfull: Yes(2) No(1)
• First we have to find out how many odd no are there I.e.
  10000/2=5000
  Then next step is to find out the no of odd no which have odd no of digit
  1: from 1 to 9 we have 5 odd no.
  2: from 101 to 999 then we have--
  999=101+(n-1)*2
  n= 450
  3: next term will start from 10001 but it is greater than 10000
  So ans = 450+5= 455
• 8 years agoHelpfull: Yes(1) No(1)
• what should do for the 2nd part not being clear...
  plz help
• 7 years agoHelpfull: Yes(1) No(0)
• suhit
  in 4 digit -4500*4=18000
  
  ans-19445
• 8 years agoHelpfull: Yes(0) No(6)
• 4998 odd no. possible b/w 1 to 10000
  
  total no of digits in odd no.s are 161500
  
  total no. of odd digits in odd no.s are 17500
• 8 years agoHelpfull: Yes(0) No(3)
• it's very simple. the given question is seem to be an a.p. because odd numbers come alternatively.
  that's why.
  Solution:-
  let the first term a=1, common difference d=2 last term l=9999
  using formula Tn=a+(n-1)*d
  9999=1+(n-1)*2
  n=5000
  so the number of odd digits will be 5000.
  
  
  
  
  
  
  
  
  
• 8 years agoHelpfull: Yes(0) No(2)
• 1 TO 10 there are 5 ODD NO.'S and 1 to 100 there are 25 odd digit no.
  and 100 to 200 againly 25 odd digit no.
  200 to 300 no. odd digit no.
  300-400 againly 25
  500-600 againly 25
  700-800 againly 25
  900-1000 aganily 25
  such that 1 to 1000 there are 5 series each contain 25 odd digit no.'s so 1000 to 2000 also there are 5 series each contain 25 odd digit no. and 3000 to 4000 same thing will happen
  so conclusion is that the total odd digit no. is 1 to 1000 numbers are 125
  so 1 to 10000 number is = 125+125+125+125+125+125=750.
• 8 years agoHelpfull: Yes(0) No(3)
• The no of odd no between 1 and 10000 is-(10000÷2)-1=4999
  and no of odd no of digits-:9+900+1=910
• 8 years agoHelpfull: Yes(0) No(4)
• First question understand--- find out the number of odd number of digits means - digits are odd
  odd digit - 1,3,5,7,9---total five digits--5 odd numbers
  2 digits --- 5*5=25 ways
  3 digits--- 5*5*5=125 ways
  4 digits --5*5*5*5=625 ways
  so 5+25+125+625= 780 numbers
• 7 years agoHelpfull: Yes(0) No(0)
• there are odd no from 0-9{1,3,5,7,9}
  1 digit no are =5
  2 digit no are =5*5=25
  3 digit no are=5*5*5=125
  4 digit no are=5*5*5*5=625
  total no are =5+25+125+625=780
• 5 years agoHelpfull: Yes(0) No(0)