There are five couples at a party.namely A&B,C&D,E&F,G&H,I&J.The couples shake their hands with the one they are acquainted with.

I)Find the total number of handshakes?
II) Find the member whom with the A does not shake the hands?(other than B)

*sry i don't remember the options

• There are totally 40 handshakes....
  
  First couple handshake with other is 8+8 = 16
  Second couple handshake with other except first couple..becuase we already add their handshakes. so ie 6+6 = 12
  Third couple handshakes is 4+4 = 8 (minus the first two couples handshake)
  Fourth couple handshakes is 2+2 = 4 (minus the first three couples handshake)
  Last couple handshakes is 0+0 = 0 (minus the first four couples handshake)
  
  so total 16+12+8+4 = 40.
• 8 years agoHelpfull: Yes(9) No(0)
• total handshakes= (2n^C2) - n ( usually formula is nC2. here couples are given so 2nC2 - n. -n is because they will not shake hand with spouse). answer is 40.
  or you can do it with another method:
  0 1 2 3 4
  a c e g i
  b d f h j
  8 7 6 5 4
  add all numbers total will be 40. just write name of couples in pairs and start with zero. in second line start with same number in backward direction.
• 8 years agoHelpfull: Yes(7) No(1)
• total handshakes =8
• 8 years agoHelpfull: Yes(3) No(11)
• i) i think ans is :90
  
  bcoz there are 10 persons
  
  so 1 person gives shake hands to 9 persons.
  lly 10 persons gives 10*9=90
  
  i i) Find the member whom with the A does not shake the hands?(other than B)
  
  it means A only.................becoz A can't give shake hand to A.
  
• 8 years agoHelpfull: Yes(1) No(0)
• total handshake=40
• 8 years agoHelpfull: Yes(1) No(0)
• Can anyone answer to the question
  II) Find the member whom with the A does not shake the hands?(other than B)
  Please ...
• 8 years agoHelpfull: Yes(0) No(0)
• Total handshakes = 40
  1st pair A and B do handshake with C&D ,E&F and so on..
  SO,
  8+8=16
  2nd pair C&D do handshake with other couple except with first couple ( because we already add their handshakes)
  SO,
  6+6=12
  3rd couple = 4+4 = 8
  4th couple = 2+2 = 4
  last couple 0 handshake.
  final = 16+12+8+4=40
• 8 years agoHelpfull: Yes(0) No(0)