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Numerical Ability
Age Problem
Six years ago, mother's age was 20 years more than the son's age. If the sum of their present ages is 34, what was the age of the mothers 6 years ago?
1) 21 years
2) 28 years
3) 34 years
4) 36 years
Read Solution (Total 3)
-
- 6years ago
Mother | son age
x+20 yrs| X yrs
Present ages
Mother +6 | son age +6
x+20+6 yrs| X +6 yrs
sum of their present ages is 34
(x+20+6)+(x+6) = 34
2x = 2 ==> x = 1
the age of the mothers 6 years ago is x+20 ==> 21 years - 8 years agoHelpfull: Yes(8) No(0)
- 1) 21 years
If present age of Mother=m and Son=s, then
6 years ago : m-6=(s-6)+20 or m-s=20 ----(i) and
Sum of present age: m+s=34 ---(ii)
From (i) & (ii), s=7, m=27
So mother's age 6 years ago=27-6=21 years - 8 years agoHelpfull: Yes(2) No(1)
- let s=son's age and m=mother's age
6yrs ago,m=s+20
at present,(s+6)+(s+20+6)=34=>s=1
m=20+1=21 - 4 years agoHelpfull: Yes(0) No(0)
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