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Arithmetic
On a school’s Annual day sweets were to be equally distributed amongst 112 children. But on that particular day, 32 children were absent. Thus the remaining children got 6 extra sweets. How many sweets was each child originally supposed to get?
Options
(1) 24
(2) 18
(3) 15
(4) Cannot be determined
Read Solution (Total 3)
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- Optn 3
32 chidrn r absent so 112-32=80
So,dey mentn dat bcz of absent children get 6 extra. Den
80*6= 480
By distributing 480 sweets equally to 32 we can find easily
480/32= 15 - 8 years agoHelpfull: Yes(2) No(0)
- x/112 = (x/(112-32))+6
x=1680
1680/112=15 - 6 years agoHelpfull: Yes(0) No(0)
- number of sweets originally=112*x
32 were absent ,numbers of students =80
they got 6 extra sweets ,number of sweets=80*(x+6)
112x=80x+480
x=15 - 5 years agoHelpfull: Yes(0) No(0)
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