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Three taps A,B and C can fill a tank in 20,30and 40 minutes respectively. All the taps are opened simultaneously and after 5 minutes tap A was closed and then after 6 minutes tab B was closed .At the moment a leak developed which can empty the full tank in 60 minutes. What is the total time taken for the completely full?
a) 24 minutes
b) 25 minutes
c) 35 minutes
d) 40 minutes
e) None of these
Read Solution (Total 1)
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- a) 24 minutes
Upto first 5 minutes A, B and C will fill 5[(1/20)+(1/30)+(1/40)]=65/120
For next 6 minutes, B and C will fill 6[(1/30)+(1/40)]=42/120
So tank filled upto first 11 minutes=(65/120)+(42/120)=107/120 so remaining tank=13/120
As 1 minutes filling with C and leakage @ 1/60 per minute= (1/40)-(1/60)=1/120
So time taken to fill remaining 13/120 tank =(13/120) /(1/120)=13 minutes
Hence total time taken to completely fill the tank= 5+6+13= 24 minutes - 8 years agoHelpfull: Yes(11) No(0)
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