Find the number of ways in which 10 players out of 14 players can be selected such that 3 particular player are always included and 2 particular players are always excluded?
1) 38
2) 36
3) 48
4) 40
5) 32

• Out of 14 players, let us element 2 particular player
  which are excluded. Now, there are 12 players for selection of these 12, three have to be included in team always. Thus remaining players are (12 – 3) = 9 and the required players for team (10 – 3) = 7. Now,
  selection cannot be done in
  9C7 ways.
  
  9C7 = 9!/7!2! = 36 ways.
• 8 years agoHelpfull: Yes(9) No(0)
• answer is 36
• 5 years agoHelpfull: Yes(0) No(1)