Find the Output.
int main(){
char a=250;
int expr;
expr= a+ !a + ~a + ++a;
printf("%d",expr);
return 0;
}
Options:249,250,0,-6

• char a = 250;
  250 is beyond the range of signed char. Its corresponding cyclic value is: -6 (-128 to 127), 0 to 127 is occupied in first 1 to 250, then it remains 122. Now this 122 is occupied by -128 to -7 and remains -6.
  
  So, a = -6
  
  Consider on the expression:
  expr= a+ !a + ~a + ++a;
  Operator! , ~ and ++ have equal precedence. And it associative is right to left.
  So, First ++ operator will perform the operation. So value a will -5
  Now,
  Expr = -5 + !-5 + ~-5 + -5
  = -5 + !-5 + 4 – 5
  
  //(to solve ~-5 first make binary of 5 then subtract 1 and convert back to decimal.)
  
  = -5 + 0 + 4 -5
  = -6
  
• 8 years agoHelpfull: Yes(2) No(0)
• Ans : -6
  1) evaluate ++a and assign it a. a=251.. but since its signed char the corresponding integer value is -5 (it exceeds 128)
  2) ~a=~251=4
  3)!a=0
  4)expr = -5+0+4+-5=-6
• 8 years agoHelpfull: Yes(1) No(3)