A 10-bit unsigned integer has the following range Options 1 0 to 1000 2 0 to 1024 3 1 to

[4 ]As the integer is unsigned so MSB would not be used to store sign bit ,to ensure that the number is negative or positive . so all 10 bits would to used to store the data bits . therefore ,the range would be 0 to 2^10-1 .
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[4] 0 to 1023 as total are 1024 starting from 0.
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10 bit unsigned that means only postive values hence 2^10 =1024 so range will be 0-1023.
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2 because unsigned start with 0
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0 to 1024
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4
because unsigned int range stats from 0
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[2] i think second one is the answer
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ans is 4th....2 ^10 -1=1023...so ans is 0 to 1023
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0 to 1023.For n bit binary number,range will be 0 to 2^n-1.
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O-1033
i.e, 0 - 2^n-1
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o to 1024 becoz range
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4. range of unsigned integer is2^n-1 hence for 10 bit it will be 1024. that is from 0 to 1023
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0 to 1023 as 10 bit unsigned integer means 2^10=1024
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1023.renge=(2^n)-1,so 1024-1=1023
3 years agoHelpfull: Yes(0) No(0)

A 10-bit unsigned integer has the following range:
Options:
[1] 0 to 1000
[2] 0 to 1024
[3] 1 to 1025
[4] 0 to 1023