What is the output and why?
#include
int main(){
int i=(char)65;
printf("%d %c %f %d",i,i,i,i);
return 0;
}

• 65(integer) A(char) 0.000000(float) 4200624(garbage)
  
• 8 years agoHelpfull: Yes(3) No(0)
• 65,A,0.000000,garbage value
• 8 years agoHelpfull: Yes(2) No(0)
• Char65=a,
  %f=65/1
  %d=65
  %c=a
• 8 years agoHelpfull: Yes(1) No(0)
• int i=(char)65 becomes
  int i=a;
  since a is not declared or it is not assigned with any values
  It wil give a errorneous output
• 8 years agoHelpfull: Yes(1) No(0)
• 65 A 65.0 65
• 8 years agoHelpfull: Yes(1) No(0)
• here it is error because _AX is undeclared. if it is declared then output will be zero
• 8 years agoHelpfull: Yes(0) No(0)
• 65,a,65/1,65
• 8 years agoHelpfull: Yes(0) No(1)
• 65/1 means?
  am getting 0..why?
  
• 8 years agoHelpfull: Yes(0) No(0)
• It will not give any output as because in print statement float is used .If we remove %f from print statement then output will be 65,A,65.
  and else if we want to get output in given program then for that we have to declare float first.
• 8 years agoHelpfull: Yes(0) No(0)
• answer will be 65 A 0.000000 65
• 7 years agoHelpfull: Yes(0) No(0)