void main()
{
int fun();
int i;
i=fun();
printf("%d",i);
}
int fun()
{
_AX=1234;
}

• It will print 1234. As it take the value of i from accumulator.
  
• 8 years agoHelpfull: Yes(3) No(0)
• _AX is undeclared . so the output is an error.
  
• 8 years agoHelpfull: Yes(3) No(0)
• It depends on compiler. if we are using turbo c , it will print 1234. In dev , it will give error saying "_AX is undeclared". It accepts in turbo c as it takes as (_ax)auxiliary variable.
• 7 years agoHelpfull: Yes(1) No(0)
• here _AX is undeclared so it is error.if it has declared then output will be zero
• 8 years agoHelpfull: Yes(0) No(3)
• it returns 1 as default
  
• 8 years agoHelpfull: Yes(0) No(1)
• same value print
• 8 years agoHelpfull: Yes(0) No(0)
• it prints 1234 as output
  
• 8 years agoHelpfull: Yes(0) No(0)
• it print the value 1234
• 7 years agoHelpfull: Yes(0) No(0)
• It will show error because in program they have not declared _AX . so you won't get any value.
• 7 years agoHelpfull: Yes(0) No(0)