the distance (in metres) to which a boy can throw astone is inversely propoertional to it's weight (in kg).he breaks the stone into three pieces whose weights (in kg) are in ratio 1:3:2. he then throws the stone one by one .the sum of the distances they cover is 22m.To what distance he can throw the unbroken stone?

• Answer : 2 meters
  
  As mentioned in the question, distance of stone is inversely proportional to its weight.
  
  the weights of 3 stones are in the ratio is 1:3:2 then the ratio of distance will be (1/1):(1/3):(1/2) or 6:2:3
  
  the total distance covered by the stones is 22m.
  
  From the ratio 6x + 2x +3x = 11x
  
  so, 11x = 22
  
  or, x=2 mts
  So he can throw the unbroken stone for a distance of 2mts
• 7 years agoHelpfull: Yes(1) No(0)
• As mentioned in the question, distance of stone is inversely proportional to its weight.
  
  so if the weights of 3 stones are in the ratio is 1:3:2 then the ratio of distance will be (1/1):(1/3):(1/2) or 6:2:3
  
  the total distance covered by the stones is 22m.
  
  let three distances be 6x,2x and 3x
  
  then 6x + 2x +3x = 11x
  
  so, 11x = 22
  
  or, x=2
  
  so the distances will be 12m, 4m and 6m respectively for the 3 stones being in the ratio by weights of 1:3:2
  
  here (1/6)th wight of the stone goes 12 m.
  
  so the unbroken stone will go (1/6)*12= 2m. (Answer)
• 7 years agoHelpfull: Yes(0) No(0)