12 men can complete any work in 36 days. 18 women can complete the same piece of work in 60 days. 8 men and 20 women work together for 20 days. If only the women were to complete the remaining work in 4 days, then how many women would be required?
1) 60
2) 74
3) 68
4) 75
5) 70

• 5) 70
  
  1 Man, 1 Day work=1/(12*36)
  1 Woman, 1 Day work=1/(18*60)
  So 8 men and 20 women's 20 days work= 20[ 8/(12*36) + 20/(18*60) ] =20/27
  Remaining work= 7/27
  If remaining work is to be completed by 'x' women in 4 days, then 4*x/(18*60)= 7/27
  => x=(7*18*60)/(27*4)=70
• 8 years agoHelpfull: Yes(9) No(1)
• Answer
  (5) 70
• 7 years agoHelpfull: Yes(0) No(2)
• 12/man can complete work in 36 days 1 man work = 1/(36*12)
  18/ women in 60 days
  1 woman work = 1/(60*18)
  both worked for 20 days ..
  1 days work (8 man +20 woman) = 1/54+1/54= 1/27;
  hence 20 days work = 20/27;
  total work =1;
  work left =1-20/27;
  hence 7/27 work left will be completed by (n)womens in 4 days is
  (4 *n)/18*60 = 7/27
  n = 70
• 7 years agoHelpfull: Yes(0) No(0)