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Permutation and Combination
Out of 5 women and 4 men, a committee of three members is to be formed in such a way that at least one member is woman. In how many different ways can this be done?
1) 60
2) 100
3) 120
4) 90
5) 80
Read Solution (Total 4)
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- 5) 80
We may have (1 woman and 2 men) or (2 women and 1 man) or (3 women).
So Required number of ways= (5C1x4C2) + (5C2x4C1) + (5C3) =(5*6) + (10*4) +(10) =80 - 7 years agoHelpfull: Yes(13) No(0)
- Answer
Possible combination
(1W & 2M)
(2W & 1M)
(3W & 0M)
number of ways= (5C1x4C2) + (5C2x4C1) + (5C3) =(5*6) + (10*4) +(10) =80 - 7 years agoHelpfull: Yes(4) No(0)
- 12C3-4C3= 80
- 6 years agoHelpfull: Yes(0) No(0)
- 60e/fknwekl/rjfewklrjfewlrjflewk/rhgerhgejrhgkjefhgkjefhgkjdfhgkjdfhgkj.dsfhgkdj.hgs;eghselu
- 4 years agoHelpfull: Yes(0) No(0)
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