In a triangle ABC,point D is on side AB and point E is on side AC,such that BCED is a trapezium.DE:BC =3:5.Calculate the ratio of the area of triangle ADE and the trapezium BCED.

• area of tri(ADE)/area of tri(ABC) = DE^2 / BC^2 since tri(ADE) -tri(ABC)
  area of tri(ADE)/area of tri(ABC) = 9/25
  area of tri(ABC)/area of tri(ADE) = 25/9
  area of tri(ABC) = area of tri(ADE) + area of trap(BCDE)
  (area of tri(ADE) + area of trap(BCDE))/area of tri(ADE) = 25/9
  1 + area of trap(BCDE)/area of tri(ADE) = 25/9
  take1on both sides
  area of trap(BCDE)/area of tri(ADE) = (25/9) - 1 = 16/9
  
  since question is asking for area of tri(ADE)/area of trap(BCDE) = 9/16
• 8 years agoHelpfull: Yes(10) No(7)