How many words can be formed using the letters of the word “CORRESPONDANCE” if the consonants are always written together?

a)182 b)184 c)216*9! d)None of thease

• (6!/2!*2!)*(9!/2!*2!*2!) = (45/2)*9!
• 8 years agoHelpfull: Yes(29) No(6)
• ans :none of these
  explanation:
  given word is correspondance
  taking consonants :- crrspndnc , total number of consonants are 9 , so it will be arranged like 9!/(2!*2!)
  again for vowel :- oeoae , total number of vowels are 5, so it will be arranged like 5!/(2!*2!)
  now finally combining both vowel and consonant , we get ,
  9!/(2!*2!) * 5!/(2!*2!) *2!= 9! * 15 ans.
• 8 years agoHelpfull: Yes(10) No(20)
• answer- none of these.
  CORRESPONDANCE.
  According to the question, we can split the word into two halves, (CRRSPNDNC) & (OEOAE). These two can be arranged among themselves in 2! ways. Now (CRRSPNDNC) can be arranged in 9!/(2!*2!*2!) ways. Similarly, (OEOAE) can be arranged in 6!/(2!*2!) ways. Since all the three cases occur together hence the answer is 2! * 9!/(2!*2!*2!) * 6!/(2!*2!) = 45*9!
• 8 years agoHelpfull: Yes(4) No(6)
• none of these
  9!/(2!*2!) * 5!/(2!*2!) *2!= 9! * 15 ans.
  
• 8 years agoHelpfull: Yes(2) No(5)
• 2! * 9!/(2!*2!*2!) * 6!/(2!*2!) = 45*9!
  repeated symbols are C,O,R,E,N
• 8 years agoHelpfull: Yes(1) No(2)
• OEOAE (CRRSPNDNC) TAKE TOTAL CONSONANT AS 1 SO TOTAL IS 6!
  THEN 6!/2!*2! BECAUSE OF REPETATION AND 9!/2!*2!*2! SOLVING THIS WE GET 45*9!
• 8 years agoHelpfull: Yes(1) No(0)
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• 8 years agoHelpfull: Yes(0) No(1)
• 9!/(2!*2!*2!)*5!/(2!2!)
  9!*15/4
• 8 years agoHelpfull: Yes(0) No(1)
• answer is 9!/2!*2! * 5!/2!*2! * 2!
  9! means any consonant can come first without repitition.
  2! means any consonants whether R or N can come first.
  similarly, definition for vowels hold
  another 2! is multiplied bcz whether vowels can come first together or whether consonants can come together first.
• 7 years agoHelpfull: Yes(0) No(1)
• ans d,
  6!*9!/2!*2!*2!*2!*2!=45/2*9!
• 5 years agoHelpfull: Yes(0) No(0)