In a class out of 150 studs participated in various games foot ball ,basket ball, cricket are 120, 130,135 respecly and 5 stud are not playing any one of then then find the least no of studs which are are playing all the games

• let the x studs are playing all the games
  and there are 5 studs whos not playing any game
  then
  120-x+130-x+135-x=150-5
  385-145=3x
  x=80
  
• 7 years agoHelpfull: Yes(20) No(19)
• *mistake above
  
  By pigeon hole principle, we have to apply this small formula
  
  (120 + 130 + 135) % 145 = 95
• 7 years agoHelpfull: Yes(8) No(4)
• 110 is correct answer
• 7 years agoHelpfull: Yes(6) No(2)
• sorry my previous post was wrong..i think correct answer should be
  let the x studs are playing all the games
  and there are 5 studs whos not playing any game
  then
  120-x+130-x+135-x=150-5
  385-145=3x
  x=80
• 7 years agoHelpfull: Yes(6) No(0)
• total (120+130+135)=385
  total number of student involve in player is 150-5=145
  therefore the least no of studnt which are playing all the game is 385-145=240
  240 ans
  
• 7 years agoHelpfull: Yes(2) No(14)
• probably it will 80
• 7 years agoHelpfull: Yes(2) No(1)
• total (135+120+135)=385
  total no students 150-5=145
  so we have 385-145=240
• 7 years agoHelpfull: Yes(2) No(3)
• can not be determine
• 7 years agoHelpfull: Yes(2) No(1)
• 100 should be the correct answer.
  we have total (125 + 130 + 135) = 390 game players.
  
  class we have 150Player students & 5 non player =145
  
  145 Player students plays at least one of these 3 games( otherwise they would come in non player's category)
  
  That is each of the player student can be either a 1 game players, or a 2 game player or a 3 game player.
  
  Also all of these 145 players students will make up 390 game players.
  
  145 students are 1 game players, then we will have 145 * 1 = 145 game
  simply for 2nd 145*2=290
  and for 3rd 145*3=435
  It is clear that to make 390 game players out of 145 player students, we need some 3 game player .even if all of 145 students were 2 game players , we can have only 145 x 2 = 290 players at most, and we are still 100 game players away from given 390 players hence least (390 - 290) = 100, 3 game player students out of 145 player students
  
  (125 + 130 + 135) % 145 = 100
• 7 years agoHelpfull: Yes(2) No(0)
• (125 + 130 + 135) % 145 = 100
  
  By pigeon hole principle
• 7 years agoHelpfull: Yes(1) No(2)
• 110 is correct but how?
  
• 7 years agoHelpfull: Yes(1) No(0)
• (120-x)+(130-x)+(135-x)=150-5-x
  385-145=2x
  240/2= x
  X = 120
  
• 7 years agoHelpfull: Yes(1) No(0)
• By pigeon hole principle,
  
  (120 + 130 + 135) % 145 = 95 (100% sure)
• 7 years agoHelpfull: Yes(1) No(0)