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Numerical Ability
Number System
last two digit in 15*51*97*63*37
Read Solution (Total 8)
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- step 1- take all the unit digit number and multiplying them 5*1*7*3*7 then we got 5. this is the unit digit.
step 2- each digit divided by 10 and multiplying all the reminder , and unit number we get 5.
ans is 55 - 8 years agoHelpfull: Yes(33) No(6)
- unit digit: take all units digit of all number and multiply them 5*1*7*3*7=735 drop tens and hundred digit so we have 5 as units digit.
tens digits:divide all number by 10 and multiply their remainder and retain only last digit(5). (15 divided by 10 gives remainder as 5 similarly 51 divided by 10 gives 1 as remainder and so on )
answer will be 55 - 8 years agoHelpfull: Yes(15) No(3)
- take the last digit of every number then multiply each number
5*1*7*3*7=735
so last 2 digit is 35 - 8 years agoHelpfull: Yes(3) No(16)
- Answer:35
Solution: 1.)multiply the unit digit of all numbers
(5*1*7*3*7)=...35
so last two digits are 35 - 8 years agoHelpfull: Yes(2) No(23)
- very first we take unit digit to all the number so we got 5 and each digit divided by 10 and multiplying all the reminder and unit digit no we get 5 so ans 55
- 8 years agoHelpfull: Yes(2) No(1)
- (10+5)*(50+1)*(100-3)*(60+3)*(40-3)
5*1*3*3*3=135
then last digit =35
- 8 years agoHelpfull: Yes(1) No(9)
- step 1- multiplying them 5*1*7*3*7 then we got 5. this is the unit digit.
step 2- divided by 10 we get 5
=55 - 8 years agoHelpfull: Yes(0) No(1)
- multiply all numbers only last two digit (55)
- 8 years agoHelpfull: Yes(0) No(3)
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