Elitmus
Exam
Logical Reasoning
Cryptography
F M A
A X X
-----------
K X F V
K X F V -
V Z M L - -
--------------
M K X Q W V
Read Solution (Total 6)
-
- In the given solution value of z and w both are same i.e 9 which is not possible.
So both given solution are wrong. - 8 years agoHelpfull: Yes(3) No(0)
- 734*
488
--------
5872
5872
2936
---------------
358192
start with z=8 or 9
v+1 = M
k+m = 8 or 9 or 10
- 8 years agoHelpfull: Yes(2) No(6)
- please explain clearly how do they get in numbers?
- 8 years agoHelpfull: Yes(0) No(0)
- will any one please explain me ....how was it come...?
- 8 years agoHelpfull: Yes(0) No(0)
- F M A
A X X
-----------------
K X F V
K X F V
V Z M L
--------------------
M K X Q W V
Check F M A*
A
----------------------
K X F V
7 3 4*
4
----------------
2 9 3 6
then
F M A*
7 3 4*
X
8
--------------------
K X F V
5 8 7 2
SO,
7 3 4*
4 8 8
--------------------
5 8 7 2
5 8 7 2*
2 9 3 6 **
--------------------
3 5 8 1 9 2 - 8 years agoHelpfull: Yes(0) No(10)
- It must be Z instead of W* or vice versa as the value can not be same for any 2 variables.
Talking bout solution K +Z=K that means Z=9(always) & A*A=_L that means A can not be 0,1,5,6 So chances are (2,3,4,7,8) but after substituting or trial error method suitable value turns out to be 4.
FM4
4XX
-------
KXFV
KXFV
V9ML
---------
MKXQZ*V
Now A*X=_V Best value can be 3 or 8 after substitution. We will find 8 as the value
that means V will be 2 (A*X=4*8) . Same thing with L=6 as (A*A=4*4)
FM4
488
-------
K8F2
K8F2
29ML
---------
MK8Q92 M=V+1 as K+9 can't be more than 16
Now after looking at these values we can easily derive remaining values as F+2=9 i.e F+V=Z . So F=7
Q= X+F+L=8+7+6=1
734
488
-------
5872
5872
2936
---------
358192 - 7 years agoHelpfull: Yes(0) No(0)
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