FMA
AXX
-----------
KXFV
KXFV
VZML
------------
MKXQWV

• Question is wrong right question is
  FMA
  AXX
  -----------
  KXFV
  KXFV
  VZML
  ------------
  MKXQZV
  
  Now solution as we can see that
  v+1=m
  k+z=k this is only possible if z=0 or z=9 but we are getting a carry in v+1=m it means that z is greater no and hence it is 9
  
  now
  FMA
  AXX
  -----------
  KXFV
  KXFV
  V9ML
  ------------
  MKXQ9V
  
  now u can see that
  f+v=9 it is possible with values like (1,8),(2,7),(3,6),(4,5)
  
  by hit and trail (1,8) not possible
  go for now (2,7)
  
  7ma
  a
  -------
  29ml
  --------
  now by hit and trial a=4
  
  7m4
  4
  --------
  29m6
  --------
  again by hit and trail
  m=3
  
  734
  4
  -------
  2936
  -------
  
  now writing whole equation
  734
  4XX
  ---------
  KX72
  KX72
  2936
  ------------
  3KXQ92
  ------------
  now X can be 3 or 8 but 3 is occupied by M so X=8
  
  734
  488
  ------
  5872
  5872
  2936
  _________
  358192
  
• 7 years agoHelpfull: Yes(10) No(2)
• 734
  488
  ------
  5872
  5872
  2936
  _______
  358192
  
• 7 years agoHelpfull: Yes(1) No(1)
• As I remember, there is Z in place of W.
  734
  488
  -------
  5872
  5872
  2936
  _______
  358192
• 7 years agoHelpfull: Yes(1) No(2)
• 734
  488
  -------
  5872
  5872
  2936
  
  --------
  358192
• 7 years agoHelpfull: Yes(0) No(3)
• 734
  488
  -------
  5872
  5872
  2936
  -----------
  358192
• 7 years agoHelpfull: Yes(0) No(1)
• Thank you, Ravi for your solution
• 7 years agoHelpfull: Yes(0) No(0)
• I gotvboth z and w values as 9 which is not accord to rule. Will any one explain it and correct answer
• 7 years agoHelpfull: Yes(0) No(0)