log(a(a(a)^1/4)^1/4)^1/4 here base is a.
option:-
a)0
b)1
c)3^0.25
d)None of these

• log(a(a(a^1/4)^1/4)^1/4
  => log(a(a^1+1/4)^1/4)^1/4
  => log(a(a^5/4)^1/4)^1/4
  =>log(a(a^5/16)^1/4
  =>log(a^1+5/16)^1/4
  =>log(a^21/16)^1/4
  =>log(a^21/64)
  =>21/64 log(a)
  =>21/64
• 8 years agoHelpfull: Yes(31) No(1)
• log (a (a(a)^1/4)^1/4)^1/4
  =log(a(a(a^1/4)^1/4)^1/4
  =1/4[log a{a(a^1/4)]^1/4
  =1/4[log a{a^1*a^1/4}]^1/4
  =1/4[log a +log( a^5/4)^1/4]
  =1/4[log a +log a^5/16]
  =1/4[log a+5/16 log a] ,,,,,,,,base is"a",so value of log a=1
  =1/4[ 1 + 5/16]
  =1/4[21/16]
  =21/64
  
• 8 years agoHelpfull: Yes(14) No(0)
• Ans. is (c)
  this equal to 1/4log(a)+log(a(a)^1/4)^1/4 .
  1/4+1/4+1/4= 3/4.
• 8 years agoHelpfull: Yes(1) No(11)
• 3/4 is the correct answer
  as value of √x√x√x......√x=x^((2-1)/2).
  therefore here root is of 1/4
  hence a^((4-1)/4)
  thatswhy log a^(3/4)=3/4(base is a, hence log a base a=1)
• 8 years agoHelpfull: Yes(0) No(0)
• log(a(a(a)^1/4)^1/4)^1/4base a
  =(1/4)[log(a(a(a)^1/4)^1/4]base a
  =(1/4)(1/4)[log(a^2*(a)^1/4]base a
  =(1/4)(1/4)(1/4)[log(a^3)] base a
  =[3(1/4)(1/4)(1/4)][loga base a]
  =3/64=
  ans
• 8 years agoHelpfull: Yes(0) No(0)