1281=±1±2±3......±n , minimum value of n

• it is notng but sum of n natural numbers which is equal to 1281 then we hqve formulq that n(n+1)/2=1281
  n^2+n=2562 ==>n^2+n-2562=0 then on by optional verificationwe get the answer
  
• 8 years agoHelpfull: Yes(9) No(1)
• n(n+1)/2= 1281
  n^2+n = 2562
  n^2+n-2562 = 0
  some deviation (n-52)(n+51) = 2652
  n= -51 or n=52
• 8 years agoHelpfull: Yes(6) No(4)
• n(n+1)/2=1281,so n*(n+1)=2562
  if n=51 then sum will be 2550,if n is 52 then 2601,by making some no genitive we can teach 2562,so minimum n value is 52
  
• 8 years agoHelpfull: Yes(2) No(1)
• Actually the question is not correct because the value of n must be integer type but we can not get a integer no here.
• 8 years agoHelpfull: Yes(2) No(0)
• n(n+1)/2=1281, n=52,-51 min value of n is 52
• 8 years agoHelpfull: Yes(0) No(0)