if p is number greater than 99 ,e is the probability of divisiblity of any even whole number p, and O is the probablity of any odd whole number divisible by p , w is probablity of any whole number divisible by p.

a) w=2e
b) e=w/2
c) o=w/2
d) either (b) or (c)

• ans is
  d)
  because e and 0 can't be more than w, so in this case only one option left. by the way option a and b are same.
• 8 years agoHelpfull: Yes(13) No(0)
• for eg any even whole number take e=2,
  any odd whole number take o=3,
  any whole number take w=6
  for eg the number which is divisible by 2,3,6 is=642
  so take option c;
  o=w/2 which means 3=6/2 ->3=3;
  so option c is correct.
• 8 years agoHelpfull: Yes(10) No(15)
• Please tell the confirmed, verified and correct Answer, please comment on this fast
• 8 years agoHelpfull: Yes(2) No(0)
• here,p>99 means 100,101,102,.............it's whole number.
  and in this set half number of element is even and odd.
  so the probablity of even(e) and probablity of odd whole number (w) would be 1/2 of in comprasion of whole number.
  so, e=w/2,o=w/2 both are correct.
• 7 years agoHelpfull: Yes(2) No(0)
• correct answer is c
• 8 years agoHelpfull: Yes(1) No(0)
• Correct ans : d
• 7 years agoHelpfull: Yes(1) No(0)
• Since p is an even nos, so only even nos will be divisible by P
  
  Let N be a set of whole nos [N1 , N2 , N3 , N4 ,N5, N6 ,N7 , N8 ,N9 , ................................. ]
  
  out of these N numbers, N/2 are evn nos and N/2 are odd numbers
  
  Since none of the odd nos will be divisble by p (as p is an even nos) so, o = 0
  
  If Q nos are divisble by p i.e nos of events is Q for both the even and whole nos,
  
  For whole nos , number of sample space is N and therefore w = Q/N
  
  and for even nos, nos of sample space is N/2 and therefore e = Q/0.5N = 2Q/N
  
  Clearly , w = e/2
• 7 years agoHelpfull: Yes(1) No(2)
• any odd number which is divisible by 2 leaves a remainder so condition c violates the given condition.
  c and d are ruled out.
• 8 years agoHelpfull: Yes(0) No(5)
• hey tell me the confirm answer
• 8 years agoHelpfull: Yes(0) No(1)