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A chemical mixture requires 2 chemicals, A and B in the proporion 3:2, this mixture is to be prepared in a tank of capacity 50 litres. Pipe A can pile the tank with chemical A in 50 minutes and pipe B can fill the tank with chemical B in 30 minutes. if both the pipes are opened when the tank is empty, how much time will it take for both the pipes to fill d tank with the proportional mixture?
A) (10,10)
B) (9,9)
C) (12,12)
D) (9,12)
E) (12,9)
Read Solution (Total 2)
-
- ans:(9,12)
chem (A) :must fill the tank by 30 litres and it takes 15 min to fill 50 litres
so, 15/50 =x/30 =>x=9
chem (B):must fill the tank with 20 litres and it takes 30 min to fill 50 litres
so, 30/50 =x/20 =>x=12 - 8 years agoHelpfull: Yes(14) No(16)
- ans:(12,9)
- 5 years agoHelpfull: Yes(2) No(4)
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