In how many possible ways can write 3240 as a product of 3 positive integers a,b and c.
a. 450
b. 420
c. 350
d. 320

• Express 3240 as a factors of prime nos
  
  3240 = 2 x 2 x 2 x 3 x 3 x 3 x 3 x 5 = 23 x 34 x 5
  
  so these 3 nos of 2's can be distributed to 3 integres a,b,c in : [3+(3-1)]C (3-1) ways i.e 5C2 = 10 ways
  
  Nos of ways in which 4 nos of 3's can be distributed to 3 integers : [4+(3-1)]C (3-1) ways i.e 6C2 = 15 ways
  
  Nos of ways in which 1 nos of 5 can be distributed to 3 integers : [1+(3-1)]C (3-1) ways i.e 3C2 = 3 ways
  
  So total ways = 10 x 15 x 3 = 450
• 8 years agoHelpfull: Yes(13) No(0)
• add numbers 3+2+4+0=9 ; add in option 4+5+0=9 both have same divisiblity
• 8 years agoHelpfull: Yes(11) No(2)
• 450 2^3*3^4*5^1 n+r-1Cr-1 where r=3 and n=3,4,1 put and multiple all the value 10*15*3
• 8 years agoHelpfull: Yes(8) No(4)
• How u are saying r=3?can u explain please
• 8 years agoHelpfull: Yes(0) No(0)
• Pavithra Selvamani, Go through the question once again, In the question they asked all possible ways that we can write 3240 as a product of 3 positive integers. From that r=3. If he asked for 4 integers then it will be 4.
• 8 years agoHelpfull: Yes(0) No(1)
• why n=3,4,1?
• 8 years agoHelpfull: Yes(0) No(0)