which of the following is power of 3?
a.2345
b.9875
c.6504
d.9833

• option c is the right answer because 6+5+0+4=15 which is divisible by 3.
  but in option a, 2+3+4+5=14 ,not divisible by 3
  in option b, 9+8+7+5=29 ,not divisible by 3
  in option d, 9+8+3+3+=23, not divisible by 3,
• 7 years agoHelpfull: Yes(11) No(3)
• sum of the digits=6+5+0+4=15 which is divisible by 3.(opt c)
• 7 years agoHelpfull: Yes(7) No(3)
• power of 3 has 1,3,7,9 in their unit digit place hence ans:d
• 7 years agoHelpfull: Yes(7) No(0)
• 2^3=8
  is 8 divisible by 3???
  i tnk the approaches are wrong
• 7 years agoHelpfull: Yes(3) No(2)
• Here power denotes perfect product or dividable number .. here 6504 only is dividable by 3
  
  answer: 6504 ( C )
• 7 years agoHelpfull: Yes(1) No(0)
• sum of digits is divisible by 3 .so,option C is right
• 7 years agoHelpfull: Yes(1) No(0)
• none of the above
• 7 years agoHelpfull: Yes(1) No(1)
• none of the above ans is right 3^7=2187, 3^8=6561,3^9=19683.
• 7 years agoHelpfull: Yes(1) No(0)
• Option c is write bcz 6504 is divisible by 3 (or)
  Sum of digits 6+5+0+4=15 which is divisible by3
  Other options are not divisible by 3
• 7 years agoHelpfull: Yes(0) No(0)
• Ans: Option c-6504
  Because 6504 is divisible by 3
• 7 years agoHelpfull: Yes(0) No(0)
• Since only option (c) 6504 adds upto 6+5+0+4= 15 is divisible by 3 therefore only 6504 is a power of 3.
• 7 years agoHelpfull: Yes(0) No(0)
• 2345/3 is not divisible by 3 similarly b and d also since option c is divisible by 3 so it is correct
• 7 years agoHelpfull: Yes(0) No(0)
• If any number is in power of 3, then it should also be divided by 3... if we see options only c.6504 is divisible by 3... soo answer is C.6504
• 7 years agoHelpfull: Yes(0) No(0)
• 6504 is a divisible by 3
• 7 years agoHelpfull: Yes(0) No(1)
• Power of 3's are always ends with 3, 9, 7, 1
• 7 years agoHelpfull: Yes(0) No(0)
• unit digit is 3 so answer is d
• 7 years agoHelpfull: Yes(0) No(0)
• Sorry guys you all are wrong
  correct ans is D)9833.
  we know that 3^1=3,3^2=9,3^3=27,3^4=81,3^5=243 and so on...
  here see last digit 1,3,9,7 only it again repeated..
  and in option there is only one that has last digit 3
• 7 years agoHelpfull: Yes(0) No(2)
• First check divisible to 3.
  2+3+4+5=14 not divisible ,9+8+7+5=29 not divisible, 6+5+0+4=15 divisible, 9+8+3+3=23 not divisible
  Here only one Number is divisible 6504 hence
  Ans c)
• 7 years agoHelpfull: Yes(0) No(0)
• in the options only 6504 is divisible by 3 with remider equal to ' 0'.
• 7 years agoHelpfull: Yes(0) No(0)
• if the number is power of 3 it should be divisible by 3 so option a is answer
• 7 years agoHelpfull: Yes(0) No(0)
• 6504
  becoz sum of digits is divisible by 3 unlike others
  
• 7 years agoHelpfull: Yes(0) No(0)
• 3,9,27,81 order is
  3,9,7,1 so ans=d
• 6 years agoHelpfull: Yes(0) No(0)
• last digit of 3^1=3, 3^2=9, 3^3= 7, 3^4= 1, 3^5= 3, 3^6=9 clearly we can see that we can never get 5 r 4 in the last digit with the power f 3 so d is the right answer
• 6 years agoHelpfull: Yes(0) No(0)
• C 6+5+0+4=15/3
• 5 years agoHelpfull: Yes(0) No(0)