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Numerical Ability
Number System
What is the maximum value of n such that 146! is perfect divisible by 5n ?
Read Solution (Total 7)
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- 146/5 + 145/25 + 146/125= 29+5+1=35 (neglect remainders).
Ans. = 35 - 8 years agoHelpfull: Yes(21) No(8)
- 146!=146*145*144*.......*1
so, 145/5=29 , so n= 29 - 8 years agoHelpfull: Yes(9) No(3)
- 146! =146*145*144*143..
so if the denominator should be a multiple of numerator then only remainder is zero.
hence largest number is 29=>(5*29)=145 no other number is present in the series that is largers than 145 - 8 years agoHelpfull: Yes(3) No(1)
- Required answer,
= [146/5] + [146/52] + [146/53];
= 29+5+1.
= 35. - 8 years agoHelpfull: Yes(1) No(2)
- Requiredanswer,=[1465]+[14652]+[14653];=29+5+1=35
- 5 years agoHelpfull: Yes(1) No(0)
- answer is 10
- 7 years agoHelpfull: Yes(0) No(4)
- 146/5 + 145/25 + 146/125= 29+5+1=35
- 5 years agoHelpfull: Yes(0) No(0)
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