What is the maximum value of n such that 146! is perfect divisible by 5n ?

• 146/5 + 145/25 + 146/125= 29+5+1=35 (neglect remainders).
  Ans. = 35
• 7 years agoHelpfull: Yes(21) No(8)
• 146!=146*145*144*.......*1
  so, 145/5=29 , so n= 29
• 7 years agoHelpfull: Yes(9) No(3)
• 146! =146*145*144*143..
  so if the denominator should be a multiple of numerator then only remainder is zero.
  hence largest number is 29=>(5*29)=145 no other number is present in the series that is largers than 145
• 7 years agoHelpfull: Yes(3) No(1)
• Required answer,
  = [146/5] + [146/52] + [146/53];
  = 29+5+1.
  = 35.
• 7 years agoHelpfull: Yes(1) No(2)
• Requiredanswer,=[1465]+[14652]+[14653];=29+5+1=35
• 4 years agoHelpfull: Yes(1) No(0)
• answer is 10
• 7 years agoHelpfull: Yes(0) No(4)
• 146/5 + 145/25 + 146/125= 29+5+1=35
• 4 years agoHelpfull: Yes(0) No(0)