find the greatest number that will divide 148 246 and 623 leaving remainders 4 6 and 11 respectively

• Hcf ( (148-4), (246-6), (623-11))=12
• 8 years agoHelpfull: Yes(9) No(5)
• 148-4=144
  246-6=240
  623-11=612
  Hence these 3 are divided by 12 leaving remainders 4 6 and 11
• 8 years agoHelpfull: Yes(6) No(0)
• hcf of 144, 240,612 is 12. 12 is the answer
• 8 years agoHelpfull: Yes(2) No(1)
• difference of the dividend and remainder gives you the divisible number
  so Hcf of ((148-4),(246-6),(623-11)
  144=12*12
  240=12*20
  623=12*51
  so the HCF is 12.
• 8 years agoHelpfull: Yes(2) No(0)
• hcf of given numbers is 12
  
• 8 years agoHelpfull: Yes(0) No(0)
• a*4/100=8 , a=800/4, a=200
  b*8/100 , b=400/8, b=50
  c=50/200, c=1/4
• 7 years agoHelpfull: Yes(0) No(2)
• 148-4=144
  246-6=240
  623-11=612
  Hence these 3 are divided by 12 leaving remainders 4 6 and 11
• 5 years agoHelpfull: Yes(0) No(0)
• Ans2
  148-4=144
  246-6=240
  623-11=612
  144-= 2*2*18
  240= 2*2*3*20
  612=2*2*
  2 great no
• 5 years agoHelpfull: Yes(0) No(0)
• We know that When a greatest number that divide x,y,z and leaves remainder a,b,c respectively = HCF of (x - a),(y - b),(z - c).
  
  Now,
  
  HCF of (148 - 4),(246 - 6),(623 - 11)
  
  = > HCF of (144, 240,612)
  
  
  Prime factorization of 144 = 2 * 2 * 2 * 2 * 3 * 3
  
  Prime factorization of 240 = 2 * 2 * 2 * 2 * 3 * 5
  
  Prime factorization of 612 = 2 * 2 * 3 * 3 * 17
  
  HCF(144,240,612) = 2 * 3 * 3 = 12.
  
  
  Hence, the greatest number is n = 12.
  
  
  Now,
  
  We have to find the remainder when n is divided by 7.
  
  
  = > 7)12(1
  
          7
  
         ---
  
          5.
  
  Therefore, the remainder is 5.
• 5 years agoHelpfull: Yes(0) No(0)
• 148-4=144,246-6=240,623-11=612
  HCF of 144,240,612 is 12.
• 4 years agoHelpfull: Yes(0) No(0)