4. What is ∑K=0283K(28KC) where 28KC
is the number of ways of choosing k items from 28 items?
a. 256
b. 3* 227
c. 329
d. 3* 427

• i dont know
  
• 8 years agoHelpfull: Yes(5) No(12)
• We know that C0+3C1+32C2+.....+3nCn=4n
  Substitute n = 28
  We get ∑K=0283K(28KC) = 428= 256
  
• 8 years agoHelpfull: Yes(4) No(3)
• 28
  ∑ 3^k (28Ck) = 28C0 + 3^1 (28C1) +3^2 (28C2) + .... + 3^28 (28C28) = (1+ 3)^28 = (4)^28= (2)^2*28= (2)^56
  k=0
• 8 years agoHelpfull: Yes(3) No(2)
• main tukka alagati to 256 lagati:D
• 7 years agoHelpfull: Yes(1) No(5)
• We know that C0+3C1+32C2+.....+3nCn=4n
  Substitute n = 28
  We get ∑K=0283K(28KC) = 428= 256
• 6 years agoHelpfull: Yes(0) No(0)