19. What is the largest number that will divide 90207, 232585 and 127986 without leaving a remainder?
a. 257
b. 905
c. 351
d. 498

• Given numbers are 90207,127986 and 232585.We want greatest number which divides given numbers.Thus we need HCF of given numbers.
  90207=3*3*3*13*257
  127986=2*3*83*257
  232585=5*181*257
  Hence 257 is required number.
• 8 years agoHelpfull: Yes(7) No(0)
• 257 is the right answer. check by options...
  
• 8 years agoHelpfull: Yes(3) No(0)
• the largest number that will divide 90207, 232585 and 127986 without leaving a remainder is 257
• 8 years agoHelpfull: Yes(1) No(0)
• For such problems, subtract largest no. with the second largest and the second largest with the smallest.
  232585-127986=104599 and 127986-90207=37779.
  Now use division method to find H.C.F.
• 8 years agoHelpfull: Yes(1) No(0)
• 257 is the right answer
• 7 years agoHelpfull: Yes(1) No(0)
• 257 i solved the ans using last number
• 8 years agoHelpfull: Yes(0) No(0)
• 257 because when divides of 90207,232585,127986 for 257 then remainder comes 0
• 8 years agoHelpfull: Yes(0) No(1)
• 257 is right answer
• 7 years agoHelpfull: Yes(0) No(0)