A man can hit a target once in 3 shots.If he fires 3 shots in succession, find the probability that he will hit his target.
A) 2/9
b)19/27
C)5/9
d)1/27

• Probability of hitting the target= 1- probability of not hitting the target
  if he hits once every 3 balls,
  probability of hitting = 1/3, probability of not hitting=2/3
  probability of not hitting the target all three times= (2/3)* (2/3)* (2/3)
  probability of hitting target = 1 -(2/3)^3
  19/7 so option B
• 8 years agoHelpfull: Yes(34) No(5)
• 1/3 + 2/3 * 1/3 + 2/3 * 2/3 * 1/3=19/27
• 8 years agoHelpfull: Yes(5) No(1)
• hit the target=1-probability of not hitting the target
  =1-p(0)
  =1-3c0*(1/3)^0*(2/3)^3
  =1-8/27
  =19/27
• 7 years agoHelpfull: Yes(2) No(0)
• any one have schneider and voltas placement paper ?? please send me link email- abhisheksingh1303037@gmail.com
• 8 years agoHelpfull: Yes(1) No(6)
• Ans= 1 - (2/3)^3 = (27-8)/27 = 19/27
  
• 8 years agoHelpfull: Yes(1) No(1)
• 1-(2*3)^3=1-8/27
  (27-8)/27=19/27
• 7 years agoHelpfull: Yes(1) No(0)
• Ans. 19/27.
• 8 years agoHelpfull: Yes(0) No(4)
• 3c1/9c3 = 1/27
• 7 years agoHelpfull: Yes(0) No(1)
• Probability of hitting the target= 1- probability of not hitting the target
  if he hits once every 3 balls,
  probability of hitting = 1/3, probability of not hitting=2/3
  probability of not hitting the target all three times= (2/3)* (2/3)* (2/3)
  probability of hitting target = 1 -(2/3)^3
  19/27
• 1 year agoHelpfull: Yes(0) No(0)