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Permutation and Combination
During a games slow held in a school, 40 students play game 1, 67 plays game 2, 46 played game 3, 8 students played game 1 & 3 games. 26 students played game 1 & 2. 28 students played game 2 & 3. 2 students played all the three games.
Q1) how maney students played game 1 but not game 2 &3 ?
a. 3
b. 8
c. 15
d. 23
Q2) how maney students played game 3 but not game 1 &2 ?
a. 12
b. 16
c. 32
d. 46
Q3)how maney students played game 2 but not game 1 &3 ?
a. 2
b. 7
c. 15
d. 37
Read Solution (Total 5)
-
- total = 40 + 67 + 46 - 8 - 26 - 28 + 2
total = 93
1) game 1 = 40
game 2 + game 3 = 67 + 46 - 28 = 85
game 1 = total - (game 2 + game 3) = 93 - 85 = 8
2) game 3 = 46
game 1 + game 2 = 40 + 67 - 26 = 81
game 3 = total - (game 1 + game 2) = 93 - 81 = 12
3) game 2 = 40
game 1 + game 3 = 40 + 46 - 8 = 78
game 2 = total - (game 1 + game 3) = 93 - 78 = 15 - 4 years agoHelpfull: Yes(5) No(0)
- we have to take venn diagram.It can give clear answer ie is only game :8 members,only game 2:15 members, only game 3:12 members.
- 7 years agoHelpfull: Yes(4) No(5)
- 1.b
2.a
3.c - 7 years agoHelpfull: Yes(2) No(9)
- 8,15,12 jhikfyu;kbvyuoi;l.mbk.n,k
- 7 years agoHelpfull: Yes(2) No(12)
- 1.8 and 2.12 and 3.15
- 7 years agoHelpfull: Yes(0) No(10)
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