pandavas Yudisthir Arjun Bhim Nakul Sahdev participate in a wrestling tournament.
Shakracharya decide one man will play 2 games at home and 2 games away.
They play only once to each other.
After finishing game Shankracharya analyze that away games are not win more than three.
None of them win equal games.
Yudhithir wins two games.
Bhim plays 2 games with arjun and yudhisthir away.
Arjun plays 1 game away with yudhisthir.
Nakul play with sahdev a home game.

Q1.Who wins maxm games?
Q2.What is difference between Bhim and nakul's winned games?
Q3.Who wins less games?

• First tings first. As per question there will be 10 games total. now as no body wins equal games,
  this means that 10 = sum of 5 non equal number . this can be only satisfied by
  10 = 0+1+2+3+4
  
  Therefore the 5 people have won followig number of games
  
  0
  1
  2 ---- Yudhishtar (given in question)
  3
  4
  
  now as only 3 away games have been won as away, this means they must be won by the player winning 3 and 4 games. as otherwise it is not possible to win 3 or 4 games as 2 games are home game and 2 are away for each player
  
  From this we can conclude that yudhishtar must have won both home games and lost both away games.Following are the 10 combinations that we can draw for these matches (g indicates it is given in question). Also note as yudhistar lost both his away games , then nakul and sehdev must have won atleast 1 game and therefore it can only be either bhim or arjun who wins 0 games.
  
  away ----- home winner
  ----------------------
  bhim Yudhi -g Yudhishtar
  bhim arjun -g
  arjun Yudhi -g Yudhistar
  Sahdev nakul -g
  Sahdev bhim
  Nakul bhim
  arjun sahdev
  yudhi sahdev sahdev
  nakul arjun
  Yudhi nakul nakul
  
  
  Now when you try with bhim winning 0 games you will get
  
  
  away ----- home winner(as per data) winner if bhim wins 0
  ----------------------
  
  bhim Yudhi -g Yudhishtar
  bhim arjun -g 1-Arjun ( as bhim wins 0 arjun must win)
  arjun Yudhi -g Yudhistar
  Sahdev nakul -g 6- as 3 games away have already be won this must be a home win
  Sahdev bhim 3-sah (as bhim wins 0 sahdev must win this)
  Nakul bhim 2- nakul (as bhim wins 0 nakul must win this)
  arjun sahdev 5-sah( based on 4 point arjun is suppose to win 1 game only)
  yudhi sahdev sahdev
  nakul arjun 4- nakul (as nakul and shedev have won 2 games they must be the ones winning 3 and 4 games because yudhishar is the one winning 2 games )
  Yudhi nakul nakul
  
  
  When you try the same with arjun winning 0 games it is not solvable so the winning counts are
  
  
  0- bhim
  1-Arjun
  2-Yudhishtar
  3-Sahdev
  4-Nakul
• 7 years agoHelpfull: Yes(5) No(0)
• 1; Bhim
  2: 4-2=2
  3: yudhisthir 0 games
• 7 years agoHelpfull: Yes(2) No(10)
• I think
  Maxm game win by Bheem.
• 7 years agoHelpfull: Yes(0) No(0)
• please explain
• 7 years agoHelpfull: Yes(0) No(0)
• I think the question is not clarity.
• 7 years agoHelpfull: Yes(0) No(0)
• somebody explain this puzzle pls
• 7 years agoHelpfull: Yes(0) No(0)
• please explain the question because question seems to be wrong.
• 7 years agoHelpfull: Yes(0) No(0)