Elitmus
Exam
Numerical Ability
Number System
if z=(6010004)^n then what is the minimum value of n for which the fourth digit for the right is a non zero no.
Read Solution (Total 4)
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- 4^5= 1024
so n= 5 - 7 years agoHelpfull: Yes(18) No(1)
- First split 6010004 as sum of 6010000 and 4,
so z=(6010000+4)^n
now as we by binomial expansion that all terms will contain at least 6010000 in multiplication except for one tern that is 4^n and therefore only that term will determine what comes in the last 4 positions.
So now the problem is reduced to what power of 4 gives a non zero in the 4th position from right.
as we know 4^5 = 1025, therefor that is the minimum value of n for z to have a non zero number in the thousand position. - 7 years agoHelpfull: Yes(11) No(0)
- plz explin clearly
- 7 years agoHelpfull: Yes(1) No(1)
- 5
6010004^5=*****1024
4^5=1024 - 7 years agoHelpfull: Yes(1) No(0)
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